Pike is a town in Wyoming County, New York. The population was 1,114 at the 2010 census.
According to the United States Census Bureau, the town has a total area of 31.2 square miles (80.8 km²), of which 31.1 square miles (80.5 km²) is land and 0.1 square mile (0.3 km²) (0.42%) is water.
The south town line is the border of Allegany County.
As of the census of 2000, there were 1,086 people, 382 households, and 283 families residing in the town. The population density was 34.9 people per square mile (13.5/km²). There were 444 housing units at an average density of 14.3 per square mile (5.5/km²). The racial makeup of the town was 96.78% White, 0.28% Black or African American, 1.29% Native American, 0.28% Asian, 0.09% from other races, and 1.29% from two or more races. Hispanic or Latino of any race were 0.55% of the population.
There were 382 households out of which 38.0% had children under the age of 18 living with them, 63.4% were married couples living together, 6.8% had a female householder with no husband present, and 25.7% were non-families. 19.9% of all households were made up of individuals and 9.2% had someone living alone who was 65 years of age or older. The average household size was 2.84 and the average family size was 3.26.
In the town, the population was spread out with 29.6% under the age of 18, 7.7% from 18 to 24, 28.3% from 25 to 44, 23.9% from 45 to 64, and 10.5% who were 65 years of age or older. The median age was 36 years. For every 100 females, there were 100.0 males. For every 100 females age 18 and over, there were 99.7 males.
The median income for a household in the town was $37,328, and the median income for a family was $41,522. Males had a median income of $30,606 versus $20,813 for females. The per capita income for the town was $14,996. About 7.0% of families and 12.6% of the population were below the poverty line, including 16.4% of those under age 18 and 4.7% of those age 65 or over.